3b^2-12/6b^2+12b/5b-10/10b^2+20b

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Solution for 3b^2-12/6b^2+12b/5b-10/10b^2+20b equation: 


b in (-oo:+oo)

3*b^2-((12/6)*b^2)+((12*b)/5)*b-((10/10)*b^2)+20*b = 0

3*b^2-2*b^2+((12*b)/5)*b-b^2+20*b = 0

12/5*b^2+20*b = 0

DELTA = 20^2-(0*12/5*4)

DELTA = 400

DELTA > 0

b = (400^(1/2)-20)/(2*12/5) or b = (-400^(1/2)-20)/(2*12/5)

b = 0 or b = -25/3

b in { -25/3, 0 }

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